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6v^2-12v-210=0
a = 6; b = -12; c = -210;
Δ = b2-4ac
Δ = -122-4·6·(-210)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-72}{2*6}=\frac{-60}{12} =-5 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+72}{2*6}=\frac{84}{12} =7 $
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